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Script not working

  Date: Dec 04    Category: Unix / Linux / Ubuntu    Views: 553
  

I'm trying to learn to use the shell and I have this script that I have seen
posted in several different places, and I want to put in my .bashrc.

However, I get the following error: line 11: syntax error near unexpected
token
line 11: syntax error "function extract()

I don't know enough yet to spot what's wrong.

Can anyone help?

Here's the script.

function extract() # Handy Extract Program.

{

if [ -f $1 ] ; then

case $1 in

*.tar.bz2) tar xvjf $1 ;;

*.tar.gz) tar xvzf $1 ;;

*.bz2) bunzip2 $1 ;;

*.rar) unrar x $1 ;;

*.gz) gunzip $1 ;;

*.tar) tar xvf $1 ;;

*.tbz2) tar xvjf $1 ;;

*.tgz) tar xvzf $1 ;;

*.zip) unzip $1 ;;

*.Z) uncompress $1 ;;

*.7z) 7z x $1 ;;

*) echo "'$1' cannot be extracted via >extract<" ;;

esac

else

echo "'$1' is not a valid file"

fi

}

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1 Answer Found

 
Answer #1    Answered On: Dec 04    

I think I see the error - it appears to be in the function declaration.

You have parens there, and I think that's causing the error.

"Declaring a function is just a matter of writing function my_func {
my_code }.
"
http://tldp.org/HOWTO/Bash-Prog-Intro-HOWTO-8.html

Missing from your script was the the interpreter path (not
sure if it was left off when you copy/pasted or if it it's
missing from your actual bash script.

On some systems this line looks like

#!/usr/local/bin/bash
or
#!/usr/bin/bash

but for portability, I usually use
#!/bin/sh
and because of systematic symlinks, it "finds" the bash
interpreter path wherever it may happen to be.

 
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