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Select Range, less last row

  Asked By: Karina    Date: Mar 11    Category: MS Office    Views: 4938
  

I want to select and copy a range of variable size. I know the the first
row of the range is from "G3:M3" However, I don't know how many rows deep
the range will be. Sometimes the Range may be ("G3:M27") or ("G3:M15").

Additionally, I want to select everything EXCEPT the last row in the range.
Also, there is other data below the first range of data that I don't want, so
using Range("G65536").End(xlUp) won't work either.

I used the following code and I keep getting Error '91' Object variable or
With block variable not set.

I think it's close to doing what I want it to do?!

Sub lastrow()

Dim lastrow As Range
Sheets("sheet1").Select
lastrow = Range("g3:m3").End(xlDown).Row - 1
Range("g3" & lastrow).Select

End Sub

Suggestions?

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1 Answer Found

 
Answer #1    Answered By: Jake Evans     Answered On: Mar 11


Try:

Sub last_row()

'Dim lastrow As Range
Sheets("sheet1").Select
lastrow = Range("g3:m3").End(xlDown).Row - 1
Range("G3:M" & lastrow).Select

End Sub


Changes made are:
1.The name of the sub; you named the sub the same as a variable  name.
2.The commenting out of the Dim line; you defined lastrow as a range
then you try 2 lines later to assign a number to it. You don't need
it.
3.Changed
Range("g3" & lastrow).Select
to
Range("G3:M" & lastrow).Select


You could tweak it a bit more by changing the line:
lastrow = Range("g3:m3").End(xlDown).Row - 1
to
lastrow = Range("g3").End(xlDown).Row - 1
since xl won't look in multiple columns for the last cell, only one,
the active cell column. Replace the G of G3 with the column letter of
the column you want to find the last entry of.

 
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