use Java Regex (only available on JDK 1.4)...
here is my code :

/*****************************************************************
import java.util.regex.*;

public class MyRegex {
public static void main(String[] args) {
myInput = "23AM";
myRegex = "^([0-9]{1,2})([AP]M)$" ;
// this regex mean : match only with a string  that have 1 or 2 num chars and
//followed by a/A or p/P and m/M ....

myPattern = Pattern.compile(myRegex);
myMatcher = myPattern.matcher(myInput);

if(myMatcher.find()){
System.out.println("Matched "+ myMatcher.groupCount());
for(int i=0; i <= myMatcher.groupCount(); i++) {
// print the matched, 0th index for indicates the global matching
System.out.println(i+" "+myMatcher.group(i));
}
} else
{
// input was invalid / not matched / not found
System.out.println("Unmatched");
}
}

private static String myRegex ; // string that contain regex pattern ;
private static Pattern myPattern ;
private static String myInput ;
private static Matcher myMatcher ;
}

That was a cool tip .. what are the other new features of jdk1.4 ?

here's my type of code, is'nt it simple??

class Charactering
{
public static void main(String args[])
{
String name = "23AM";
char c;
String a="", b="";
for(int i=0; i< name.length(); i++)
{
c=name.charAt(i);
if ( Character.isDigit(c))
{
a += c;
continue;
}
else
{
b+=c;
}
}
System.out.println(a);
System.out.println(b);
}
}

As best practice you might want to consider using a
StringCharacterIterator object to loop over the string  and a
StringBuffer instead of +=

I think using regex still the best (and the coolest) tricks...
your only need 5-10 line code to solve this