/*------------------- Sum of n terms of 1/n -------------------*/
                

main()                                                      
   {                                                           
       float  sum, n, term ;                                   
       int    count = 1 ;                                      
                                                               
       sum = 0 ;                                               
       printf("Enter value of n\n") ;                          
        scanf("%f", &n) ;                                      
       term = 1.0/n ;                                          
       while( count <= n )                                     
       {
            sum = sum + term ;                                 
            count++ ;                                          
       }                                                       
       printf("Sum = %f\n", sum) ;                             
   }

Output                                                      
   Enter value of n                                            
   99                                                          
   Sum = 1.000001                                              
   Enter value of n                                            
   143                                                         
   Sum = 0.999999