Logo 
Search:

Assembly Language Articles

Submit Article
Home » Articles » Assembly Language » GeneralRSS Feeds

Program that prompts the user to enter two binary numbers of up to 8 digits each, and print their sum on the next line in binary...

Posted By: Easy Tutor     Category: Assembly Language     Views: 7166

An AL program that prompts the user to enter two binary numbers of up to 8 digits each, and print their sum on the next line in binary. If the user enters an illegal character, he or she should be prompted to begin again. Each input ends with a carriage return.

Code for Program that prompts the user to enter two binary numbers of up to 8 digits each, and print their sum on the next line in binary... in Assembly Language

 .MODEL SMALL
 .STACK 100H

 .DATA
   PROMPT_1  DB  0DH,0AH,'Enter the first binary number ( max 8-digits ) : $'
   PROMPT_2  DB  0DH,0AH,'Enter the second binary number ( max 8-digits ) : $'
   PROMPT_3  DB  0DH,0AH,'The SUM of given binary numbers in binary form is : $'
   ILLEGAL   DB  0DH,0AH,'Illegal character. Try again.$'

 .CODE
   MAIN PROC
     MOV AX, @DATA                ; initialize DS
     MOV DS, AX

     JMP @START_2                 ; jump to label @START_2

     @START_1:                    ; jump label
       LEA DX, ILLEGAL            ; load and display the string ILLEGAL 
       MOV AH, 9
       INT 21H

     @START_2:                    ; jump label
       XOR BX, BX                 ; clear BX

       LEA DX, PROMPT_1           ; load and display the string PROMPT_1
       MOV AH, 9
       INT 21H

       MOV CX, 8                  ; initialize loop counter
       MOV AH, 1                  ; set input function

       @LOOP_1:                   ; loop label
         INT 21H                  ; read a character

         CMP AL, 0DH              ; compare AL with CR
         JNE @SKIP_1              ; jump to label @SKIP_1 if AL!=0DH

         CMP CX, 8                ; compare CX with 8
         JE @START_1              ; jump to label @START_1 if CX=8
         JMP @EXIT_LOOP_1         ; jump to label @EXIT_LOOP_1

         @SKIP_1:                 ; jump label
           AND AL, 0FH            ; convert ascii into decimal code
           SHL BL, 1              ; shift BL towards left by 1 position
           OR BL, AL              ; set the LSB of BL with LASB of AL
       LOOP @LOOP_1               ; jump to label @LOOP_1 if CX!=0

       @EXIT_LOOP_1:              ; jump label

       LEA DX, PROMPT_2           ; load and display the string PROMPT_2
       MOV AH, 9
       INT 21H

       MOV CX, 8                  ; initialize loop counter
       MOV AH, 1                  ; set input function

       @LOOP_2:                   ; loop label
         INT 21H                  ; read a character

         CMP AL, 0DH              ; compare AL with CR
         JNE @SKIP_2              ; jump to label @SKIP_2 if AL!=0DH

         CMP CX, 8                ; compare CX with 8
         JE @START_2              ; jump to label @START_2 if CX=8
         JMP @EXIT_LOOP_2         ; jump to label @EXIT_LOOP_2

         @SKIP_2:                 ; jump label
           AND AL, 0FH            ; convert ascii into decimal code
           SHL BH, 1              ; shift BH towards left by 1 position
           OR BH, AL              ; set the LSB of BH with LASB of AL
       LOOP @LOOP_2               ; jump to label @LOOP_2 if CX!=0

       @EXIT_LOOP_2:              ; jump label

       LEA DX, PROMPT_3           ; load and display the string PROMPT_3
       MOV AH, 9
       INT 21H

       ADD BL, BH                 ; add BL and BH
       JNC @SKIP                  ; jump to label @SKIP if CF=1
         MOV AH, 2                ; print the digit 1 i.e. carry
         MOV DL, 31H
         INT 21H

       @SKIP:                     ; jump label

       MOV CX, 8                  ; initialize loop counter
       MOV AH, 2                  ; set output function

       @LOOP_3:                   ; loop label
         SHL BL, 1                ; shift BL towards left by 1 position
         JC @ONE                  ; jump to label @ONE if CF=1
         MOV DL, 30H              ; set DL=0
         JMP @DISPLAY             ; jump to label @DISPLAY
               
         @ONE:                    ; jump label
           MOV DL, 31H            ; set DL=1

         @DISPLAY:                ; jump label
           INT 21H                ; print the character
       LOOP @LOOP_3               ; jump to label @LOOP_3 if CX!=0

     MOV AH, 4CH                  ; return control to DOS
     INT 21H
   MAIN ENDP
 END MAIN
  
Share: 



Easy Tutor
Easy Tutor author of Program that prompts the user to enter two binary numbers of up to 8 digits each, and print their sum on the next line in binary... is from United States. Easy Tutor says

Hello Friends,

I am Free Lance Tutor, who helped student in completing their homework.

I have 4 Years of hands on experience on helping student in completing their homework. I also guide them in doing their final year projects.

I have share many programs on this website for everyone to use freely, if you need further assistance, than please contact me on easytutor.2ya [at the rate] gmail [dot] com

I have special discount scheme for providing tutor services. I am providing tutor service to students from various contries, currently most of my students are from United States, India, Australia, Pakistan, Germany, UK and Canada.

I am also here to expand my technical network to receive more opportunity in my career, make friends to help them in resolving their technical problem, learn and share my knowledge, If you like to be my friend, Please send me friend request.

Thanks,
Happy Programming :)

 
View All Articles

Related Articles and Code:


 

Other Interesting Articles in Assembly Language:


 
Please enter your Comment

  • Comment should be atleast 30 Characters.
  • Please put code inside [Code] your code [/Code].

 
Dolar Hridoy from Bangladesh Comment on: Nov 28
There is a part of a question that,"If the user enters an illegal character, he or she should be prompted to begin again". But, If I enter illegal characters like: 12121212, as233510; the sum is still coming in binary number. Please, give me a solution that how can I fix it.

View All Comments